![SOLVED: Use the linear approximation of f(x, y)=e^x^2+y at (0,0) to estimate f(0.01,-0.02) . Compare with the value obtained using a calculator. SOLVED: Use the linear approximation of f(x, y)=e^x^2+y at (0,0) to estimate f(0.01,-0.02) . Compare with the value obtained using a calculator.](https://cdn.numerade.com/ask_previews/651fc15e-44c2-4aa3-8336-7ea5cc99edbf_large.jpg)
SOLVED: Use the linear approximation of f(x, y)=e^x^2+y at (0,0) to estimate f(0.01,-0.02) . Compare with the value obtained using a calculator.
![Find a Linear Approximation to a Function of Two Variables and Estimate a Function Value | Math Help from Arithmetic through Calculus and beyond Find a Linear Approximation to a Function of Two Variables and Estimate a Function Value | Math Help from Arithmetic through Calculus and beyond](http://img.youtube.com/vi/PmvHEE_8okI/0.jpg)
Find a Linear Approximation to a Function of Two Variables and Estimate a Function Value | Math Help from Arithmetic through Calculus and beyond
![SOLVED:Use the linear approximation of f(x, y)=e^x^2+y at (0,0) to estimate f(0.01,-0.02) . Compare with the value obtained using a calculator. SOLVED:Use the linear approximation of f(x, y)=e^x^2+y at (0,0) to estimate f(0.01,-0.02) . Compare with the value obtained using a calculator.](https://cdn.numerade.com/previews/a539c50b-fe13-4bc6-b55d-a222b47d5c73_large.jpg)
SOLVED:Use the linear approximation of f(x, y)=e^x^2+y at (0,0) to estimate f(0.01,-0.02) . Compare with the value obtained using a calculator.
![Use linear approximation to estimate the value. Compare with the value given by a calculator. (Use decimal notation. Give answer to four decimal places.) \sqrt{(3.93)(6.06)(5.09)} \approx ? Calculate the the percentage error Use linear approximation to estimate the value. Compare with the value given by a calculator. (Use decimal notation. Give answer to four decimal places.) \sqrt{(3.93)(6.06)(5.09)} \approx ? Calculate the the percentage error](https://homework.study.com/cimages/multimages/16/appro4376835722842277686.jpg)